Question

(3x-³ y³)-² tell me the answer please​

Answer 1

Step-by-step explanation:

$\huge \tt {( {3x}^{ - 3} {y}^{3}) }^{ - 2} \\ \\ \huge \tt {( \frac{3{y}^{3}}{ {x}^{3} } })^{ - 2} \\ \\ \huge \tt {( \frac{ {x}^{3} }{3{y}^{3}} })^{ 2} \\ \\ \huge \tt { \frac{ {x}^{6} }{9{y}^{6}} }$

Answer 2

(3x-³ y³)-² = x⁶/9y⁶

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