√3x(√3x-√2)-√2(√3x-√2)
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√3x(√3x-√2) -√2(√3x-√2)
Taking (√3x-√2) common, we get
= (√3x-√2)(√3x-√2)
= (√3x-√2)²
= (√3x)²+(√2)²-2×(√3x)×(√2)
/* (a-b)² = a²+b²-2ab */
= 3x²+2-2√6x
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