Question

3x-4=0 , x-y=-6 pair of equation by substitution method (full method with x and y value written)

Answer 1

GIVEn

3x-4y=0 , x-y=-6 pair of equation by substitution method

TO FINd

Find the value of x and y

SOLUTIOn

✒ Given equations

• 3x - 4y = 0 --(i)
• x - y = - 6 --(ii)

✞ From eqⁿ (i)

→ x - y = - 6

→ x = y - 6

✞ Put the value of " x " in equation (i)

→ 3x - 4y = 0

→ 3(y - 6) - 4y = 0

→ 3y - 18 - 4y = 0

→ - y = 18

→ y = - 18

✞ Again put the value of " y " in eqⁿ (ii)

→ x - y = -6

→ x - (-18) = - 6

→ x + 18 = -6

→ x = -18 - 6 = - 24

Therefore,

Required value of x = - 24

Required value of y = -18

Answer 2

$\underline{\boxed{\bold\red{Question}}}$

$3x-4=0---(1)$

$x-y=-6---(2)$

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

$\underline{\boxed{\bold\blue{Answer}}}$

$Form \: eqn(1) ,\: we \: get$

$\leadsto3x-4=0$

$\leadsto3x=4$

$\leadsto x= \frac{4}{3} ---(3)$

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

$substituting \: the \: value \: of \: eqn (3) \: in \: eqn (2)$

$\leadsto\frac{4}{3}-y=-6$

$\leadsto\frac{4}{3}+ \frac{6×3}{1×3}=y$

$\leadsto\frac{4}{3}+ \frac{18}{3}=y$

$\leadsto\frac{4+18}{3}=y$

$\leadsto y= \frac{22}{3} ---(4)$

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

$\star \: x=\frac{4}{3}$

$\star \: y= \frac{22}{3}$

[Hope this helps you.../]