(3x+4)² + (3x-2)²=(6x+5) (3x-2) +12
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Answer:
(1–3x)²/(3x+1)²-(2–3x)²/(3x+2)²<0
{(3x-1)(3x+2)}²-{(3x-2)( 3x+1)}²
/(3x+1)²(3x+2)²<0
(9x²+3x-2)²-(9x²-3x-2)²/(3x+1)²(3x+2)²
(6x)(18x²-4)/~~~~<0
→x(3x+√2)(3x-√2)/(3x+1)²(3x+2)²<0
sign-digram solving :
--(-2/3)- -(-√2/3)++(-1/3) ++(0)- -(√2/3) ++
solutions ：
(-∞,-2/3)∪(-2/3,-√2/3)∪(0,√2/3)
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