Math, asked by shampatush, 11 months ago

(3x-4)(2x^2-5x+1) - (2x -1)(3x^2+7x-5)​

Answers

Answered by bihudas2007
1

Answer:

-15x-12x^2-9

Step-by-step explanation:

(3x-4)(2x^2-5x+1)-(2x-1)(3x^2+7x-5)

={3x×(2x^2+5x+1)-4×(2x^2-5x+1)}-{2x×(3x^2+7x-5)-1×(3x^2+7x-5)}+-

={(6x^3+15x+3x)-(8x^2+20x-4)}-{(6x^3+7x^2-10x)-(3x^2+7x-5)}

={6x^3+15x+3x-8x^2-20x-4}-{6x^3+7x^2-10x-3x^2-7x+5}

=6x^3-2x-8x^2-4-6x^3-4x^2+17x-5

= -15x-12x^2-9

Answered by kavyasaxena106
1

ucfeivucfeive s e e e. e e e e

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