Question

3x/4-2y/3=5,2x/5+3y/5=17
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Answer 1

Answer:

2x3+3y5−17=03x4+2y3−19=0By cross−multiplication, we getx[35×(−19)]−[23×(−17)]=−y[23×(−19)]−[34×(−17)]=1[(23×23)−(34×35)]x−575+343=−y−383+514=149−920x−115=−y112=1−1180⇒x−115=1−1180⇒

2x/3 + 3y/5 = 17

(10x+9y=255)/15

Hence, 10x+9y=255

Let x be 2

10*2 +9y=255

20+9y=255

9y=255-20

9y=235

y=235/9

So, x=2, y=26.11....

3x/4+2y/3=19

(9x+8y=288)/12

9x+8y=288

Let x be 3

hence, 27+8y=288

8y=288-27

8y=261

y=261/8

So, x=3 and y=32.625