Math, asked by divyeshkher19, 9 months ago

3x/4-2y/3=5,2x/5+3y/5 by substitution method​

Answers

Answered by aditya9726
1

Answer:

By substitution method

3x/4-2y/3=5

2x/5+3y/5=0

then by substituting,

x=60-8y/9

putting these value in equation 2nd

2*(60-8y/9)+3y =0

120-16y+27 =0

147-16y=0

-16y=-147

minus minus cancel out

16y=147

y=147/16

y=9.1875

putting value of y in equation 1st

so we get,

x=51.83333333........

so, x= 51.84.

Hope it helps you

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