Question

(3x^4)^3 = 3^27. find x​

Answer 1

Solution →

${(3 {x}^{4} )}^{3} = {3}^{27}$

${3}^{3} \times {x}^{12} = {3}^{27}$

${x}^{12} = {3}^{27} \times {3}^{ - 3} \\ {x}^{12} = {3}^{24} \\ x = {3}^{2}$

$x = 9$

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Answer 2

(3x^4)^3 = 3^27
(3^3)[(x)^4]^3 = 3^27
(3^3)(x^12) = 3^27
x^12 = (3^27)/( 3^3)
x^12 = 3^(27-3)
x^12 = 3^24
x^12 =(3^2)^12
Comparing both sides we get
x = 3^2
x = 9