(3x-4)³-(x+1)³/(3x-4)³+(x+1)³=61/189 Solve the equation.
Answers
Answer:
x = 3
Step-by-step explanation:
(3x-4)³-(x+1)³/(3x-4)³+(x+1)³=61/189
=> 189(3x-4)³ - 189(x+1)³ = 61(3x-4)³ + 61(x+1)³
=> (189 - 61)(3x-4)³ = (61 + 189)(x+1)³
=> 128(3x-4)³ = 250(x+1)³
=> 64(3x-4)³ = 125(x+1)³
=> 4³(3x-4)³ = 5³(x+1)³
Taking cube root both sides
=> 4(3x - 4) = 5(x + 1)
=> 12x - 16 = 5x + 5
=> 7x = 21
=> x = 3
Verification :
(9 - 4)³ -(3+1)³ /( 9-4)³ -(3 + 1)³
= (5³ - 4³)/(5³ + 4³)
= (125 - 64)/(125 + 64)
= 81/169
Answer:
Step-by-step explanation:hola mate
here is ur answer
(3x-4)³-(x+1)³/(3x-4)³+(x+1)³=61/189
=> 189(3x-4)³ - 189(x+1)³ = 61(3x-4)³ + 61(x+1)³
=> (189 - 61)(3x-4)³ = (61 + 189)(x+1)³
=> 128(3x-4)³ = 250(x+1)³
=> 64(3x-4)³ = 125(x+1)³
=> 4³(3x-4)³ = 5³(x+1)³
Taking cube root both sides
=> 4(3x - 4) = 5(x + 1)
=> 12x - 16 = 5x + 5
=> 7x = 21
=> x = 3
Verification :
(9 - 4)³ -(3+1)³ /( 9-4)³ -(3 + 1)³
= (5³ - 4³)/(5³ + 4³)
= (125 - 64)/(125 + 64)
= 81/169