(3x+4)(3x-5) how to do the sum by using identities
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Using the identity (x+a)*(x+b)
Shobana13:
(x+a)(x+b)= x^2+x (a+b)+ab so, (3x+4)(3x-5)=(3x)^2-3x (4-5)+[4×(-5)] = 9x^2-12x+15x-20 = 9x^2+3x-20
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(x+a)(x-y)
3 is the coeffecient of x.
Substitute values according to that
3 is the coeffecient of x.
Substitute values according to that
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