Question

[3x/4]-[(x-1)/2]=[(x-2)/3]
Find the value and verify it.

Answer 1

Answer:

Step-by-step explanation:Let us rearrange the equation 3x/4 – (x-1)/2 – (x-2)/3 = 0 By taking LCM for 4, 2 and 3 which is 12 (9x – (x-1)6 – (x-2)4)/12 = 0 (9x – 6x + 6 – 4x + 8)/12 = 0 (-x + 14)/12 = 0 By cross-multiplying -x + 14 = 0 x = 14 Let us verify the given equation now, 3x/4 – (x-1)/2 = (x-2)/3 By substituting the value of ‘x’ we get, 3(14)/4 – (14-1)/2 = (14-2)/3 42/4 – 13/2 = 12/3 (42 – 26)/4 = 4 16/4 = 4 4 = 4Read more on Sarthaks.com - https://www.sarthaks.com/664655/solve-the-equationand-also-check-your-results-3x-4-x-1-2-x-2-3

Answer 2

Answer:

x=14

Step-by-step explanation:

[3x/4]-[(x-1)/2]=[(x-2)/3]

Taking 4 and 2 L.C.M we get 4

Therefore

{3x-2(x-1)}/4=(x-2)/3

(3x-2x+2)/4=(x-2)/3

(x+2)/4=(x-2)/3

Cross multiplying we get,

3(x+2)=4(x-2)

3x+6=4x-8

6+8=4x-3x

14=x

Therefore

x=14