Question

3x-4/y=1 , 2x-3/y=2. find it by elimination method​

Answer 1

Answer:

3x+4y=10 …………..(1)

2x−2y=2 (or) x−y=1 …………(2)

(1) ⇒(3x+4y=10)1

(2) ⇒(x−y=1)3

_____________________

3x+4y=10

3x−3y=3

_____________________

7y=7

∴y=1

Put y=1 in (1) we get 3x+4×1=10

3x=10−4=6

∴x=

3

6

=2

Hence x=2,y=1.

Answer 2

Answer:

$\frac{3x - 4}{y} = 1 \: \: \:$

$3x - 4 = y$

$3x - y - 4 = 0$

$2(3x - y - 4 = 0)$

$6x - 2y - 8 = 0 \: \: \: \: - - - (i)$

$\frac{2x - 3}{y} = 2$

$2x - 3 = 2y$

$2x - 2y - 3 = 0$

$3(2x - 2y - 3 = 0)$

$6x - 6y - 9 = 0 \: \: \: - - - (ii)$

$\huge\mathbb\fcolorbox{white}{purple}{★ by equating I & ii★}$

y. = \frac{-1}{4}

x= \frac{7}{4}