3x - 4y - 1= 0
2x - 8y + 5 = 0
___
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Hi,
Here's ur answer:-
3x-4y-1 = 0
=> 3x-4y = 1
=> 6x-8y = 2---(¡)
2x-8y+5 = 0
=> 2x - 8y = -5
=> 6x -24y = -15----(¡¡)
Subtracting (¡¡) from (¡),
6x-8y = 2
6x -24y = -15
__________
24y-8y = 2+15
=> 16y = 17
=> y = 17/16
3x-4y = 1
=> 3x - 17/4 = 1
=> 3x = 17/4 +1 = 21/4
=> x = 7/4
So, x = 7/4, y = 17/16
HOPE IT HELPS (^_^)☺
Please mark BRAINLIEST
Here's ur answer:-
3x-4y-1 = 0
=> 3x-4y = 1
=> 6x-8y = 2---(¡)
2x-8y+5 = 0
=> 2x - 8y = -5
=> 6x -24y = -15----(¡¡)
Subtracting (¡¡) from (¡),
6x-8y = 2
6x -24y = -15
__________
24y-8y = 2+15
=> 16y = 17
=> y = 17/16
3x-4y = 1
=> 3x - 17/4 = 1
=> 3x = 17/4 +1 = 21/4
=> x = 7/4
So, x = 7/4, y = 17/16
HOPE IT HELPS (^_^)☺
Please mark BRAINLIEST
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