Math, asked by 7898266190, 3 months ago

(3x-4y+1) ^2 : solve ​

Answers

Answered by vaishubh1707
3

Answer:

9x²+16y²+6x-8y-24xy+1

Step-by-step explanation:

(3x-4y+1)²

= [(3x-4y) +1]²

by using Identity (a+b)²=a²+b²+2ab

= (3x-4y)²+(1)²+2(3x-4y)(1)

by using Identity (a-b)²=a²+b²-2ab

= 9x²+16y²-24xy+1+6x-8y

= 9x²+16y²+6x-8y-24xy+1

Answered by Anonymous
20

Step-by-step explanation:

 \:  \:  \sf \:  {(3x - 4y + 1)}^{2}

Now expand the square

 \:  \:  \sf \: (3x  - 4y + 1)(3x - 4y + 1)

Now distribute the number

 \:  \:  \sf \: 3x(3x - 4y + 1) - 4y(3x - 4y + 1) + 1(3x - 4y + 1)

Now again distribute the number

 \:  \:  \sf \: 9 {x}^{2}  - 12xy + 3x - 4y(3x - 4y + 1) + 1(3x - 4y + 1)

Now find the answer

 \:  \:  \sf \: 9 {x}^{2}  - 24xy + 16 {y}^{2} + 6x - 8y + 1

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