Question

3x-4y-1 ,2x-y-5 solve by substitution method​

Answer 1

3x-4y-1=0 ......1

2x-y-5=0

2x=5+y

x=(5+y)÷2

put in equation 1

3((5+y)÷2)-4y-1=0

(15+3y)÷2-4y=1

(15+3y)÷2-8y÷2=1

(15+3y-8y)÷2=1

(15-5y)÷2=1

5(3-y)÷2=1

3-y=2÷5

-y=2/5-3

-y=2/5-15/5

-y=-13/5

y=13/5

put in equation 1

3x-4(13/5)-1=0

3x-52/5=1

3x=1+52/5

3x=57/5

x=57/5×3

x=19/5

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hope it's helpful

Answer 2

3x-4y=1.............(1)*2
2x-y =5..............(2)*3

6x-8y=2
6x-3y=15
- + -
……..........
-5y=-13
y=13/5

3x-4y=1
3x-4(13/5)=1
3x=1+52/5
3x=57/5
x=57/15