Question

3x+4y=10,2x-2y=2 ans by elemination method​

Answer 1

Answer: x = 2, y = 1

Step-by-step explanation:

ELIMINATION METHOD

3x+4y=10------>1

2x-2y=2-------->2

3x+4y=10

2×1=4x-4y=4

______

7x=14

x=14/7

x=2

sub x=2 in 2

2x-2y=2

2(2)-2y=2

4-2y=2

-2y=2-4

-2y=-2

y=1

sub x and y in 1

3x+4y=10

3(2)+4(1)=10

6+4=10

10=10

VERIFY:--

2x-2y=2

2(2)-2(1)=2

4-2=2

2=2

Answer 2

Answer:

x=2 ; y= 1

Step-by-step explanation:

given, 3x+4y=10 ------eq1

          2x-2y=2 ----------eq2

here from eq2- we can take 2 as common.

         then eq-2 (gets modified) to x-y=1-----eq2

therefore,

               3x+4y=10------eq1

               x  - y = 1--------eq2      {adding both the equations}

      i.e      3x+4y=10

                +x  - y = 1   {here let us consider to eliminate 'y'}

then to eliminate y

            3x+4y=10    x1(whole multiplied by 1)

          +x  - y = 1       x4(whole multiplied by 4)

then,

                3x+4y=10  

               +4x -4y =4  

            =  7x=14  ----(here +4y and -4y get cancelled)

           = x=2

then the value of y will be:   (here, to find y we shuld substitute the value of x in any one of the original equation)

       then, when x=2

             3x+4y=10

         => 3(2)+4y=10

         => 4y=10-6

        => y=1

          therefore, x=2 and y=1

Hope it helps you:) All the best!!