3x+4y=10,2x-2y=2 solve by substitution method
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Answered by
167
3x +4y =10
2x - 2y =2
2x =2 +2y
x = 2 +2y/2
3×2+2y/2 +4y =10
6 +6y/2 +4y =10
6+ 6y +8y/2 =10
14y +6 =20
14y = 20-6
14y = 14
y =14/14
y =1
2x - 2×1 =2
2x - 2 =2
2x =2+2
2x =4
x =4/2
x =2
I hope it helps u
2x - 2y =2
2x =2 +2y
x = 2 +2y/2
3×2+2y/2 +4y =10
6 +6y/2 +4y =10
6+ 6y +8y/2 =10
14y +6 =20
14y = 20-6
14y = 14
y =14/14
y =1
2x - 2×1 =2
2x - 2 =2
2x =2+2
2x =4
x =4/2
x =2
I hope it helps u
Answered by
1
The value of x is 2 and value of y is 1
Given:
Two equations 3x+4y=10,2x-2y=2
To Find:
The value of x and y
Solution:
3x+4y=10
4y = 10-3x
y = 10/4-3x/4
Put ithe value of y in equation 2x-2y=2
2x- 10/2+3x/2=2
4x-10+3x=4
7x=14
x=2
put the value of x in equation y = 10/4-3x/4
y = 1
Hence, the value of x is 2 and the value of y is 1.
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