Question

3x-4y=10
2x+3y=20

GIVE ME THE ANSWER IN DETAIL...​

Answer 1

Answer:

3x-4y=10 equation 1

2x+3y=20 equation 2

multiply equation 1 by 2 and equation 2 by 3

3x-4y=10-(i) 2x+3y=20

x2 x3

----------------- ---------------

6x-8y=20-(iii) 6x+9y=60-(iv)

subtracting equation 3 and 4 we get

6x-8y=20

-6x-9y= -60

------------------

-y= -40

y=40

put y=40 in equation in 1

3x-4y=10

3x-4(40)=10

3x-160=10

3x=10+160

3x=170

x=170/3

x=57(rounding off)

therefore value of x and y is 57, 40

Step-by-step explanation:

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Answer 2

Answer:

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