3x + 4y = 10
2x + 5y=9
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Answer:
By substitution method,
3x+4y=10 & 2x−2y=2⇒2(x−y)=2⇒x−y=1 ___ (2)
∴x=y+1→(1).
Substituting in equation (2).
∴3x+4y=10⇒3(y+1)+4y=10
⇒3y+3+4y=10⇒7y=7⇒y=1
∴x=1+1=2
∴x=2,y=1
Answered by
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➜ [ 3x + 4y = 10 ] ____ (i) eq.
➜ [ 2x + 5y = 9 ] ____ (ii) eq.
➜ 3x + 4y = 10
➜ 3x = 10 - 4y
➜ x = (10 - 4y) / 3
Now let's solve eq. (ii)...
➜ 2x + 5y = 9
➜ 2x = 9 - 5y
➜ x = (9 - 5y) / 2
On solving for [x]
➜ 2 (10 - 4y) = 3 (9 - 5y)
➜ 20 - 8y = 27 - 15y
➜ 15y - 8y = 27 - 20
➜7y = 7
➜ y = 1
By putting in eq(i) ...
➜ 3x + 4y = 10
➜ 3x + 4 = 10
➜ 3x = 6
➜ x = 2
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