3x-4y=10;4x+3y=5 solve by substitution method
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x=2 and y= -1
Step-by-step explanation:
3x-4y=10 .....eq(1)
4x+3y=5 ......eq(2)
from eq(1)
3x-4y=10
3x=10+4y
x=4y+10 ......eq(3)
3
substitute (3) in (2)
4(4y+10)+3y=5
3
16y+40+9y=5
3
25y +40=15
25y=15-40
y=-25/25
y= -1 .......eq(4)
substitute (4) in (3)
x=4( -1)+10
3
x= -4+10
3
x= 6/3
x=2
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