Question

3x-4y=10 ; 4x-3y=5 solve this by simultaneous method

Answer 1

Answer:

Step-by-step explanation:

eq1-eq2

3x-4y-4x+3y=10+5

-x-y=15

x= -y-15

Put x =-y-15

3(-y-15)-4y=10

-7y-45=10

y=-55/7

Put. y=-55/7

x=290/21

Answer 2

Answer:

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