Question

3x+4y=10 and 2x-2y=2solve subtution method​

Answer 1

Step-by-step explanation:

let

3x= 10-4y

x= 10-4y/3

keep the value of x in eque.2

2(10-4y)/3=2

20-8y/3=2

20-8y=6

-8y= 6-20

-8y= -14

y==14/8

y=7/4

then keep the value of y in equeletral. 1

10-4*7/4/3

10-7/3

3/3

x=1

check

3x+4y=10

3*1+4*7/4=10

3+7. =10

RHS.