3x+4y=10 x3 + y3=6 what is the minimum value of 3x+11y=?
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3x+4y=10......(1)
3x+3y=6.........(2)
3x+11y.....(3)
subtract eq 2 from 1
y=4
put in (2) y=4
3x+3(4)=6
3x+12=6
3x=6-12
3x= -6
x=-6/3
x= -2
put x= -2 and y=4 in (3)
3(-2)+11(4)=-6+44=38
Minimum value is 38
3x+3y=6.........(2)
3x+11y.....(3)
subtract eq 2 from 1
y=4
put in (2) y=4
3x+3(4)=6
3x+12=6
3x=6-12
3x= -6
x=-6/3
x= -2
put x= -2 and y=4 in (3)
3(-2)+11(4)=-6+44=38
Minimum value is 38
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