Question

3x-4y+11 = 0 3x-4y+5 = 0 find the minimum distance between the line

Answer 1

See these are two parallel lines,

3x+4y=9 and

3x+4y=7.5

The formula for distance between two parallel lines

ax+by=c1 and

ax+by=c2 is,

d=c2−c1a2+b2√

where ′d′ denotes the distance between the two parallel lines.

Hence the answer should be,

d=9−7.532+42√=1.55=310

Therefore, the distance is 310 .

$See these are two parallel lines,</h3><h3></h3><h3>3x+4y=93x+4y=9 and</h3><h3></h3><h3>3x+4y=7.53x+4y=7.5</h3><h3></h3><h3>The formula for distance between two parallel lines</h3><h3></h3><h3>ax+by=c1ax+by=c1 and</h3><h3></h3><h3>ax+by=c2ax+by=c2 is,</h3><h3></h3><h3>d=c2−c1a2+b2√d=c2−c1a2+b2</h3><h3></h3><h3>where ′d′′d′ denotes the distance between the two parallel lines.</h3><h3></h3><h3>Hence the answer should be,</h3><h3></h3><h3>d=9−7.532+42√=1.55=310d=9−7.532+42=1.55=310</h3><h3></h3><h3>Therefore, the distance is 310310.</h3><h3></h3><h3>$

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Answer By shreyas

Answer 2

Answer: The distance between the two lines is 6 units.

Step-by-step explanation: There is a full explanation for this but here I tell you a simple trick. If two lines are parallel then the distance between them will be equal to the difference in the constants in the given equations. In this example, the distance between the lines is 11-5=6.