3x+4y=12,6x+8y=20
solve it by elimination and substitution methods
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Answer:
there is no value of x and y satisfy the both eq. ...
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Given:
- 3x + 4y = 12 -------- [Equation 1]
- 6x + 8y = 20 -------- [Equation 2]
To find:
The values of x and y
Solution:
Firstly, let's multiply Equation 1 with 2.
2(3x + 4y) = 2(12)
➥ 6x + 8y = 24 -------- [Equation 3]
Subtracting Equation 1 from Equation 3,
6x + 8y = 24
{+} 6x + 8y = 20
0 ≠ 4
So, the following equations will form parallel lines and so they do not have any solution,
∴ There is no value of x and y which can satisfy the given equations.
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