3x+4y=12 and 7x+5y=2 solve linear equation by substitution method
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Answer:
3x+4y=12
that means 3x=12-4y
x=(12-4y) / 3
Substitute value of x in 2nd eq. i.e 7x+5y=2
7{(12-4y) / 3 } + 5y = 2
(84-28y ) /3 +5y=2
84-28y+15y=6 by taking LCM
84-13y=6
13y= 84-6=78
y=78/13
y=6
put value of y in eq. 1
x= (12-24) /3 = -12/3 = -4
it means x= -4 , y = 6
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