3x=4y+15 ; y+x+2=0 please answer the question
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Step-by-step explanation:
3x-4y-15 = 0 …(1)
x+y+2 = 0 …(2)
3x+3y+6 = 0 …(2a)
Subtract (1) from (2a) to get
3y+4y+6+15=0, or
7y+21 = 0, or
y+3 = 0, or
y = -3.
From (2), x-3+2=0, or x-1 = 0, or x = 1.
Hence x=1, y = -3
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