3x-4y=16;2×-3y=10 using elimination method
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y = 2 substitute in eq(1)
3x -4(2) =16
3x-8=16
3x=16+8
3x = 24
x=24/3
x= 8
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Answer:
3x-4y=16
2x-3y=10
3x-4y(2x-3y)=16-10
3x-4y-2x-3y=6
x-7y=6
x=6+7y
6+7y-7y=6
y=1
x=6+7*1
X=13
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