3x+4y=17,4x-3y=6 by substitution method
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Given :-
3x+4y=17
4x-3y=6
To Find:-
The Values of x and y by the substitution method
Method Used:-
We should substitute the value of x by substituting the y on the other side
Solution:-
=> 3x+4y=17
=> 4x-3y=6
=> 4x-3y=6
=> 4x=6+3y
=> x=6+3y/4
=> 3x+4y=17
=> 3[6+3y/4]+4y=17
=> 18+9y/4+4y=17
=> 18+9y+16y/4=17
=> 18+25y/4=17
=> 18+25y= 17×4
=> 25y=68-18
=> 25y=50
=> y=2
Conclusion:-
The value of y is 2 and the value of x is 3
3x+4y=17
3x+8=17
3x=9
x=3
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