Question

3x+4y+2=0 4x-5y-13=0 in. Substitution method

Answer 1

Answer:

Step-by-step explanation:

3x+4y+2=0

=>3x+4y=-2

4x-5y-13=0

=>4x-5y-13-2=0-2                                       [Subtracting both sides by -2]

=>4x-5y-15=-2

Therefore, 3x+4y=4x-5y-15=-2

=>3x+4y=4x-5y-15

=>3x-4x=-5y-4y-15

=>-x=-9y-15

=>x=-(-9y-15)

=>x=9y+15

3x+4y=-2

=>3(9y+15)+4y=-2

=>27y+45+4y=-2

=>31y=-2-45

=>31y=-47

=>y=$\frac{-47}{31}$

=>y=$-1\frac{16}{31}$

x=9y+15

=>x=9*$\frac{-47}{31}$+15

=>x=$\frac{-423}{31}$

=>x=$-13\frac{20}{31}$+15

=>x=$2-\frac{20}{31}$

=>x=$\frac{42}{31}$

=>x=$1\frac{11}{31}$

Therefore, y=$-1\frac{16}{31}$

                 x=$1\frac{11}{31}$