(3x^4y^2) (2x^2y^3) for x=1 and y=2
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Answer:
(3x4y2) (2x2y3)
(3 × 14 × 22) × (2 × 12 × 23)
(3 × 1 × 4) × (2 ×1 ×8)
= 12 × 16 = 192
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