(3x-4y)2-(5z)2 factorize it using (a+b)(a-b)
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(3x-4y-5z)(3x-4y+5z)will be obtained after factorization it
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Q. (3x-4y)2-(5z)2
(3x + -4y) * 2 + -1(5z) * 2
Reorder the terms for easier multiplication:
2(3x + -4y) + -1(5z) * 2
(3x * 2 + -4y * 2) + -1(5z) * 2
(6x + -8y) + -1(5z) * 2
Remove parenthesis around (5z)
6x + -8y + -1 * 5z * 2
Reorder the terms for easier multiplication: 6x + -8y + -1 * 5 * 2z
Multiply -1 * 5
6x + -8y + -5 * 2z
Multiply -5 * 2
6x + -8y + -10z
Factor out the Greatest Common Factor (GCF), '2'.
2(3x + -4y + -5z)
Final result:
2(3x + -4y + -5z)
(3x + -4y) * 2 + -1(5z) * 2
Reorder the terms for easier multiplication:
2(3x + -4y) + -1(5z) * 2
(3x * 2 + -4y * 2) + -1(5z) * 2
(6x + -8y) + -1(5z) * 2
Remove parenthesis around (5z)
6x + -8y + -1 * 5z * 2
Reorder the terms for easier multiplication: 6x + -8y + -1 * 5 * 2z
Multiply -1 * 5
6x + -8y + -5 * 2z
Multiply -5 * 2
6x + -8y + -10z
Factor out the Greatest Common Factor (GCF), '2'.
2(3x + -4y + -5z)
Final result:
2(3x + -4y + -5z)
ana205:
Or by using the identity , (3x-4y-5z)(3x-4y+5z) may be your answer. This is another process
I think it is square not we should multiply it with 2
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