Math, asked by deepikavats2008, 16 days ago

3x( 4y-2+5z) from 7(xy-5z+4)

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Answered by fantasticArt007

Answer:

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Subtract

3x( 4y-2+5z) from 7(xy-5z+4)

Solution➡

$7(xy - 5z + 4) - (3x(4y - 2 + 5z)) \\ = 7xy - 35z + 28 \\ - (12xy - 6x + 15xz) \\ = 7xy - 35z + 28 - 12xy + 6x \\ - 15xz \\ = - 5xy - 35z + 28 + 6x - 15xz \\$

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3x( 4y-2+5z) from 7(xy-5z+4) ​

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Your question ➡

Solution➡

3x( 4y-2+5z) from 7(xy-5z+4)