Question

(3x+4y)² find the answer by using identities ​

Answer 1

Answer:

Step-by-step explanation:

a+b)^2=a^2+b^2+2ab

given

(3x+4y)^2

=(3x)^2+(4y)^2+2(3x)(4y)

=9x^2+16y^2+24xy

Answer 2

$\huge{\underline{\underline{\mathtt{\purple{Question}}}}}$

• (3x+4y)² find the answer by using identities

$\huge{\underline{\underline{\mathtt{\purple{Solution}}}}}$

By applying this identity

(a+b)²= a²+b²+2ab to solve this question

So,

$\large\implies\sf (3x+4y)^2$

$\large\implies\sf (3x)^2+(4y)^2+2×3x+4y$

$\large\implies\sf 9x^2+16y^2+24xy$

$\huge\underline\frak\red{Identities}$

• (a+b)² = a²+b²+2ab
• (a-b)² = a²+b²-2ab
• a²-b² = (a+b)(a-b)
• a³-b³ = (a-b)(a²+ab+b²)
• a³+b³ = (a+b)(a²-ab+b²)
• (a+b)³ = a³+b³+3ab(a+b)
• (a-b)³ = a³-b³-3ab(a-b)