(3x+4y)²
Using suitable identities,find product
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Answered by
9
Answer:
first law of identity:
(a + b)² = a² + 2ab + b²
So,
(3x + 4y)² = (3x)² + (2)(3x)(4y) + (4y)²
= 9x² + 24xy + 16y²
Answered by
0
Answer:
9x² + 24xy + 16y²
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