Question

3x-4y=2,x+4y=10 solve it by elimination method answer =3,7/4

Answer 1

Step-by-step explanation:

Add both equations

3x-4y+x+4y=10+2

4x=12

therefore, x=3

putting x=3 in equation 2

3+4y=10

4y=7

therefore, y=(7/4)

Answer 2

Step-by-step explanation:

by elimination method.

by elimination method.3x-4y=2---(1)

by elimination method.3x-4y=2---(1)x+4y=10---(2)

by elimination method.3x-4y=2---(1)x+4y=10---(2)multiply the 2nd eq. with 3

by elimination method.3x-4y=2---(1)x+4y=10---(2)multiply the 2nd eq. with 33(x+4y=10)

by elimination method.3x-4y=2---(1)x+4y=10---(2)multiply the 2nd eq. with 33(x+4y=10)3x+12y=30 ---(3)

by elimination method.3x-4y=2---(1)x+4y=10---(2)multiply the 2nd eq. with 33(x+4y=10)3x+12y=30 ---(3) subtract 1st eq from 3rd.

by elimination method.3x-4y=2---(1)x+4y=10---(2)multiply the 2nd eq. with 33(x+4y=10)3x+12y=30 ---(3) subtract 1st eq from 3rd. 3x+12y=30

by elimination method.3x-4y=2---(1)x+4y=10---(2)multiply the 2nd eq. with 33(x+4y=10)3x+12y=30 ---(3) subtract 1st eq from 3rd. 3x+12y=30-3x-4 y=-2

by elimination method.3x-4y=2---(1)x+4y=10---(2)multiply the 2nd eq. with 33(x+4y=10)3x+12y=30 ---(3) subtract 1st eq from 3rd. 3x+12y=30-3x-4 y=-2_______

by elimination method.3x-4y=2---(1)x+4y=10---(2)multiply the 2nd eq. with 33(x+4y=10)3x+12y=30 ---(3) subtract 1st eq from 3rd. 3x+12y=30-3x-4 y=-2_______0x+16y=28

by elimination method.3x-4y=2---(1)x+4y=10---(2)multiply the 2nd eq. with 33(x+4y=10)3x+12y=30 ---(3) subtract 1st eq from 3rd. 3x+12y=30-3x-4 y=-2_______0x+16y=28y= 28/16=19/8

by elimination method.3x-4y=2---(1)x+4y=10---(2)multiply the 2nd eq. with 33(x+4y=10)3x+12y=30 ---(3) subtract 1st eq from 3rd. 3x+12y=30-3x-4 y=-2_______0x+16y=28y= 28/16=19/8put the value of y in Ist eq

by elimination method.3x-4y=2---(1)x+4y=10---(2)multiply the 2nd eq. with 33(x+4y=10)3x+12y=30 ---(3) subtract 1st eq from 3rd. 3x+12y=30-3x-4 y=-2_______0x+16y=28y= 28/16=19/8put the value of y in Ist eq3x-4y=2

by elimination method.3x-4y=2---(1)x+4y=10---(2)multiply the 2nd eq. with 33(x+4y=10)3x+12y=30 ---(3) subtract 1st eq from 3rd. 3x+12y=30-3x-4 y=-2_______0x+16y=28y= 28/16=19/8put the value of y in Ist eq3x-4y=23x-4(19/8)=2

by elimination method.3x-4y=2---(1)x+4y=10---(2)multiply the 2nd eq. with 33(x+4y=10)3x+12y=30 ---(3) subtract 1st eq from 3rd. 3x+12y=30-3x-4 y=-2_______0x+16y=28y= 28/16=19/8put the value of y in Ist eq3x-4y=23x-4(19/8)=23x-19/2=2

by elimination method.3x-4y=2---(1)x+4y=10---(2)multiply the 2nd eq. with 33(x+4y=10)3x+12y=30 ---(3) subtract 1st eq from 3rd. 3x+12y=30-3x-4 y=-2_______0x+16y=28y= 28/16=19/8put the value of y in Ist eq3x-4y=23x-4(19/8)=23x-19/2=2Take LCM of 1 and 2

by elimination method.3x-4y=2---(1)x+4y=10---(2)multiply the 2nd eq. with 33(x+4y=10)3x+12y=30 ---(3) subtract 1st eq from 3rd. 3x+12y=30-3x-4 y=-2_______0x+16y=28y= 28/16=19/8put the value of y in Ist eq3x-4y=23x-4(19/8)=23x-19/2=2Take LCM of 1 and 26x/2-19/2=2

by elimination method.3x-4y=2---(1)x+4y=10---(2)multiply the 2nd eq. with 33(x+4y=10)3x+12y=30 ---(3) subtract 1st eq from 3rd. 3x+12y=30-3x-4 y=-2_______0x+16y=28y= 28/16=19/8put the value of y in Ist eq3x-4y=23x-4(19/8)=23x-19/2=2Take LCM of 1 and 26x/2-19/2=26x-19=4

by elimination method.3x-4y=2---(1)x+4y=10---(2)multiply the 2nd eq. with 33(x+4y=10)3x+12y=30 ---(3) subtract 1st eq from 3rd. 3x+12y=30-3x-4 y=-2_______0x+16y=28y= 28/16=19/8put the value of y in Ist eq3x-4y=23x-4(19/8)=23x-19/2=2Take LCM of 1 and 26x/2-19/2=26x-19=46x=4+19

by elimination method.3x-4y=2---(1)x+4y=10---(2)multiply the 2nd eq. with 33(x+4y=10)3x+12y=30 ---(3) subtract 1st eq from 3rd. 3x+12y=30-3x-4 y=-2_______0x+16y=28y= 28/16=19/8put the value of y in Ist eq3x-4y=23x-4(19/8)=23x-19/2=2Take LCM of 1 and 26x/2-19/2=26x-19=46x=4+196x=23

by elimination method.3x-4y=2---(1)x+4y=10---(2)multiply the 2nd eq. with 33(x+4y=10)3x+12y=30 ---(3) subtract 1st eq from 3rd. 3x+12y=30-3x-4 y=-2_______0x+16y=28y= 28/16=19/8put the value of y in Ist eq3x-4y=23x-4(19/8)=23x-19/2=2Take LCM of 1 and 26x/2-19/2=26x-19=46x=4+196x=23x=23/6

by elimination method.3x-4y=2---(1)x+4y=10---(2)multiply the 2nd eq. with 33(x+4y=10)3x+12y=30 ---(3) subtract 1st eq from 3rd. 3x+12y=30-3x-4 y=-2_______0x+16y=28y= 28/16=19/8put the value of y in Ist eq3x-4y=23x-4(19/8)=23x-19/2=2Take LCM of 1 and 26x/2-19/2=26x-19=46x=4+196x=23x=23/6x=23/6 and y=19/8