Question

3X-4Y+22=0
4X-3Y+13=0 solve by elimination method ​

Answer 1

Answer:

x=2

y=7

(2,7)

Step-by-step explanation:

Try with Y

(x3)-> 9x-12y=-66

(x4)-> 16x-12y=-52

________________

(-) -> -7x = -14

________________

so x = 2

to equation (1)

6-4y=-22

-4y=-28

y=7

Answer 2

x = 2 and y = 7

Step-by-step explanation:

given equations :

3x+ 4y +22=0

4x-3y+13 =0

solving by elimination method

multiply the equation 3x+ 4y +22=0 by 4

we get 12x-16y = -88..(1)

multiply the equation 4x-3y+13 =0 by 3

we get 12x-9y = -39..(2)

solving 1 and 2

12x-16y=-88

12x-9y=-39

we get

-7y=-49

y = 7

put the value of y in equation 1

12x-16y = -88

12x -16(7) = -88

12x = -88 + 112

12x = 24

x = 2

hence. The value of x = 2 , and y = 7

#Learn more:

2x+3y=0

3x+4y=5

solve this by substitution method and elimination method?

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