Question

3x+4y=25, 5x-6y=9 solve by substitute methode​

Answer 1

Step-by-step explanation:

Given -

3x + 4y = 25

5x - 6y = 9

To Find -

Value of x and y by substitution method.

Now,

= 3x + 4y = 25

= 3x = 25 - 4y

• = x = 25 - 4y/3

Substituting the value of x on

5x - 6y = 9

= 5(25 - 4y/3) - 6y = 9

= 125 - 20y/3 - 6y = 9

= 125 - 20y - 18y/3 = 9

= 125 - 38y/3 = 9

= 125 - 38y = 27

= 125 - 27 = 38y

= 98 = 38y

= y = 98/38

• = y = 49/19

Now,

Substituting the value of y on

3x + 4y =25

= 3x + 4(49/19) = 25

= 3x + 196/19 = 25

= 57x + 196/19 = 25

= 57x + 196 = 25 × 19

= 57x + 196 = 475

= 57x = 475 - 196

= 57x = 279

= x = 279/57

= x = 93/19

Hence,

The value of x is 93/19

and

The value of y is 49/19

Verification -

Substituting the value of x and y on 3x + 4y = 25

= 3(93/19) + 4(49/19) = 25

= 279/19 + 196/19 = 25

= 279 + 196/19 = 25

= 475/19 = 25

= 25 = 25

LHS = RHS

Hence,

Verified..

Answer 2

$\huge \mathfrak{Answer:-}$

$\implies$ x = 93/19

$\implies$ y = 49/19

$\large\underline\mathrm{Given:-}$

• 3x + 4y = 25
• 5x - 6y = 9

$\large\underline\mathrm{To \: find}$

• Value of x and y.

$\large\underline\mathrm{Solution}$

$\implies$ 3x + 4y = 25

$\implies$ 3x = 25 - 4y

$\implies$ x = 25 - 4y/3

$\large\underline\mathrm{The \: value \: of \: x \: on \: 5x \: - \: 6y \: = \: 9}$

$\implies$ 5x - 6y = 9

$\implies$ 5(25 - 4y/3) - 6y = 9

$\implies$ 125 - 20y - 18y/3 = 9

$\implies$ 125 - 38y/3 = 9

$\implies$ 125 - 38 = 27

$\implies$ 125 - 27 = 38y

$\implies$ 98 = 38y

$\implies$ y = 98/38

$\large\underline\mathrm{The \: value \: of \: y \: on \: 3x \: + \: 4y \: = \: 25}$

$\implies$ 3x + 4(49/19) = 25

$\implies$ 3x + 196/19 = 25

$\implies$ 57x + 196/19 = 25

$\implies$ 57x + 196 = 25 × 19

$\implies$ 57x = 475 - 196

$\implies$ 57x = 279

$\implies$ 57x = 279/57

$\implies$ x = 93/19

$\large\underline\mathrm{hence,}$

$\large\underline\mathrm{the \: value \: of \: x \: is \: 93/19 \: and \: y \: is \: 49/19.}$

$\large\underline\mathrm{Hope \: it \: helps \: you \: plz \: mark \: me \: brainlist}$