3x+4y=28 and 5x-2y=12, then find the value of x and y
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Answer:
this is the answer of the question
x=4, y=4
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Step-by-step explanation:
3x+4y=28
5x-2y=12 ×2
elimination method ,
so we get ,
13x=52
x=4
applying eq 1 , to find y,
3x+4y=28
3(4)+4y=28
12+4y=28
4y= 28-12
4y= 16
y=4,
hence x=4 and y=4
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