(3x + 4y)^3 + (3x-4y)^3
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hope it helps you
plss Mark brainliest
plss Mark brainliest
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jiyagarwal06:
I don't think this is the answer
Answered by
86
= (3x +4y)^3 + (3x - 4y)^3
= 27x^3 + 64y^3 + 3*3x*4y(3x+4y) + 27x^3 - 64y^3 - 3*3x*4y(3x-4y)
= 27x^3 + 64y^3 + 36xy(3x+4y) + 27x^3 - 64y^3 - 36xy(3x-4y)
= 27x^3 + 64y^3 + 108x^2y + 144xy^2 + 27x^3 - 64y^3 -108x^2y + 144xy^2
= 54x^3 + 288xy^2
= 27x^3 + 64y^3 + 3*3x*4y(3x+4y) + 27x^3 - 64y^3 - 3*3x*4y(3x-4y)
= 27x^3 + 64y^3 + 36xy(3x+4y) + 27x^3 - 64y^3 - 36xy(3x-4y)
= 27x^3 + 64y^3 + 108x^2y + 144xy^2 + 27x^3 - 64y^3 -108x^2y + 144xy^2
= 54x^3 + 288xy^2
Thank you so much.
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