Math, asked by spharichandan75, 11 months ago


(3x+4y) (3x-4y) (9x^2+16y^2)=?​

Answers

Answered by lathadeviummadi70
7

Answer:

81x^4-256y^4

Step-by-step explanation:

(a+b)(a-b)=a^2-b^2

(3x+4y)(3x-4y)(9x^2+16y^2)

=(9x^2-16y^2)(9x^2+16y^2)

=81x^4-256y^4

Answered by SANCHICHAUDHARY
3

Answer:

81x^4 - 256y^4

Step-by-step explanation:

(a+b)(a-b)=(a^2-b^2)

(3x – 4y) (3x + 4y) ( 9 ^2 + 16 ^ 2 )

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