Question

(3x+4y) (3x-4y) using identities
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Answer 1

$(3x + 4y)(3x - 4y)$

$( {3x)}^{2} - ( {4y)}^{2}$

$9 {x}^{2} - 16 {y}^{2}$

Answer 2

Answer:

(3x+4y)(3x-4y)

=(3x)^2-(4y)^2

=9x^2-16y^2