Question

(3x+4y)(3x-8y) solve by using suitable identities.​

Answer 1

✨ QuesTion :-

( 3x + 4y ) ( 3x - 4y )

Solve by using suitable identities.

✨ SoluTion :-

$\sf \blue{ ( a + b ) ( a - b ) = (a)² - ( b ) ²}$

☘ ( 3x + 4y ) ( 3x - 4y ) = ( 3x )² - ( 4y )²

☘ 9x² - 16y²

✨ KnOw MoRe :-

$\sf \green {(a+b)²=(a²)+(b)²+2ab}$

$\sf \red {(a-b)²=(a)²+(b)²-2ab}$

$\sf \color{gray}{ (x+a)(x+b)= x²+(a+b)x+ab}$

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✿ Hope it helps you :)

Answer 2

Answer :

• (3x +4y) (3x - 8y) = 9x² - 3xy² - 12xy

Given :

• (3x + 4y) (3x - 8y)

Solution :

↝ (3x + 4y) (3x - 8y)

↝ 3x(3x - 8y) + 4y (3x - 8y)

↝ 9x² - 24xy + 12xy - 32y²

↝ 9x² - 32y² - 12xy

Hence , (3x +4y) (3x - 8y) = 9x² - 3xy² - 12xy

(a + b) (a - b) = a² - b²

More Explanation:

• (a + b) ² = a² + 2ab + b²
• (a - b)² = a² - 2ab + b²
• a² - b² = (a + b) (a - b)
• (x + a) (x + b) = x² + (a + b) x + ab
• (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca