Question

(3x – 4y) (4x²y + 3xy²); x = 2, y=-1​

Answer 1

Answer:

= [{(3×2)-{4×(-1)}] × [{4×(2×2)×(-1)} + {3×2(-1×2)}]

= [{(3×2)-{-4}] × [{4×4×-1} + {6×(-2)}]

= [6+4] × [{16×-1}+(-12)]

= 10×[{-16+(-12)}]

= 10×[-38]

= -380