Question

3x+4y-5=0 ,9/2x-6y+15/2=0 by cross multiplication method​ solve by full method​

Answer 1

Answer:

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SoLUTioN :-

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given,

-3x + 4y= 5

=> 4y = 5 +3x

=> y = (5+3x)/4------------------(i)

and

9/2x - 6y +15/2 =0

=> 9/2x = 6y -15/2

(now putting the value of y from equation (i)

=> 9/2x = [6×(5+3x)/4] - 15/2

=> 9/2x = (15+9x)/2 - 15/2

=> 9/2x = 15+9x-15/2

=> 9/2x = 9x/2

=> 9 ×2 = 9x × 2x

=> 18 = 18x²

=> 18/18 = x²

=> 1 = x²

=> x = √1

=> x = 1---------------------(ii)

(now putting the value of x in equation (i) )

y = (5+3x)/4

=>y = (5+3×1)/4

=> y = 8/4

=> y =2

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hence, x= 1 and Y=2

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