Question

3x + 4y = 5 and 2x + 3y = 3, then the value of x is

Answer 1

$\texttt{\textsf{\large{\underline{Solution}:}}}$

Given:

$\sf \implies 3x + 4y = 5 - (i)$

$\sf \implies 2x + 3y = 3 - (ii)$

We have to find out the values of x. We will solve this problem using elimination method.

Multiplying (i) by 3, we get:

$\sf \implies 9x + 12y =15 - (iii)$

Multiplying (ii) by 4, we get:

$\sf \implies 8x + 12y = 12 -(iv)$

Subtracting (iv) from (iii), we get:

$\sf \implies x = 3$

We can also find out the value of y. Substituting the value of x in (i), we get:

$\sf \implies 3 \times 3 + 4y = 5$

$\sf \implies 9 + 4y = 5$

$\sf \implies 4y = 5 - 9$

$\sf \implies 4y = - 4$

$\sf \implies y = -1$

Therefore:

$\implies \begin{cases} \sf x = 3 \\ \sf y = - 1\end{cases}$

$\texttt{\textsf{\large{\underline{Steps To Solve}:}}}$

• Multiply one or both the equations by a number to transform them so that any one variable is eliminated by addition or subtraction.
• Solve the resulting single variable equation and substitute the value of the variable into any one of the equation to find out the value of the other variable.

Answer 2

Answer:

Given:

$\sf \implies 3x + 4y = 5 - (i)$

$\sf \implies 2x+ 3y = 3 - (ii)$

We have to find out the values of x.

Multiplying (i) by 3, we get:

$\sf \implies 9x + 12y =15 - (iii)$

Multiplying (ii) by 4, we get:

$8x + 12y = 12 -(iv)$

Subtracting (iv) from (iii), we get:

$\sf \implies 9x + 12y =15 \\ \: \: \: \: \: \: \: \: \: - 8x + 12y = 12$

1x=3

Therefore x=3

find out the value of y. Substituting the value of x in (i), we get:

$3 \times 3 + 4y = 5$

$9 + 4y = 5$

$4y = 5 - 9$

$4y = - 4$

$\sf \implies y = -1$

Therefore:

$\huge\pink{(x ,\: y)} = \pink{(3 ,\: - 1)}$