Math, asked by Anonymous, 9 months ago

-3x+4y=5 and 9/2x-6y+15/2=0 has..... solutions

Answers

Answered by HEARTIE

$<body aquacolor=orange>$

$\large\orange{}$ $<font color=purple>$

$\huge{\boxed{\mathcal\pink{\fcolorbox{red}{purple}{SoLUTioN :-}}}}$

given,

-3x + 4y= 5

=> 4y = 5 +3x

=> y = (5+3x)/4------------------(i)

and

9/2x - 6y +15/2 =0

=> 9/2x = 6y -15/2

(now putting the value of y from equation (i)

=> 9/2x = [6×(5+3x)/4] - 15/2

=> 9/2x = (15+9x)/2 - 15/2

=> 9/2x = 15+9x-15/2

=> 9/2x = 9x/2

=> 9 ×2 = 9x × 2x

=> 18 = 18x²

=> 18/18 = x²

=> 1 = x²

=> x = √1

=> x = 1---------------------(ii)

(now putting the value of x in equation (i) )

y = (5+3x)/4

=>y = (5+3×1)/4

=> y = 8/4

=> y =2

______________________¢________________

hence, x= 1 and Y=2

➻❥T꙰H꙰A꙰N꙰K꙰Y꙰O꙰U꙰➻❥

♡ＬＯＶＥＹＯＵＲＳＥＬＦ♡

$<body bgcolor=pink>$

$\large\orange{}$ $<font color=purple>$

Answered by riyakhairwal20

Answer:

is this is unique sol. ??

Previous Question

Next Question