-3x+4y=5 and 9/2x-6y+15/2=0 has..... solutions
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8
w
given,
-3x + 4y= 5
=> 4y = 5 +3x
=> y = (5+3x)/4------------------(i)
and
9/2x - 6y +15/2 =0
=> 9/2x = 6y -15/2
(now putting the value of y from equation (i)
=> 9/2x = [6×(5+3x)/4] - 15/2
=> 9/2x = (15+9x)/2 - 15/2
=> 9/2x = 15+9x-15/2
=> 9/2x = 9x/2
=> 9 ×2 = 9x × 2x
=> 18 = 18x²
=> 18/18 = x²
=> 1 = x²
=> x = √1
=> x = 1---------------------(ii)
(now putting the value of x in equation (i) )
y = (5+3x)/4
=>y = (5+3×1)/4
=> y = 8/4
=> y =2
______________________¢________________
hence, x= 1 and Y=2
_________________________
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Answered by
1
Answer:
is this is unique sol. ??
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