3x+4y=5 transform into intercept form
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10th
Maths
Pair of Linear Equations in Two Variables
Reducing a Pair of Equations to Linear Form
Reduce the equation 3x + 4y...
MATHS
Reduce the equation 3x+4y−5=0 to intercept form.Hence find the length of the segment intercepted between the axes.
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ANSWER
The given equation is 3x+4y−5=0
⇒3x+4y=5$$
Dividing both sides by 5, we get
⇒
5
3x
+
5
4y
=1
⇒
3
5
x
+
4
5
y
=1 which is the required intercept form.
Here x−intercept=a=
3
5
and x−intercept=b=
4
5
∴The length of the segment intercepted between the axes=
a
2
+b2
=
(
3
5
)
2
+(
4
5
)
2
=5
9
1
+
16
1
=5
9×16
16+9
=5
12
25
=
12
25
units
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