3x+4y+5z=18 ,2x_y+8z=13, 5x_2y+7z=20 show that
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2×(3x+4y+5z)=2×18
3×(2x-y+8z)=3×13
after equ.
11y-14z=-3 ....(1)
5×(2x-y+8z)=5×13
2×(5x-2y+7z)=2×20
after equ...
-y+26z=25 .....(2)
equ..(1)&(2)
11y-14z=-3
11×(-y+26z)=11×25
after solutions
272z=272
z=272/272
z=1
x=3
y=1
3×(2x-y+8z)=3×13
after equ.
11y-14z=-3 ....(1)
5×(2x-y+8z)=5×13
2×(5x-2y+7z)=2×20
after equ...
-y+26z=25 .....(2)
equ..(1)&(2)
11y-14z=-3
11×(-y+26z)=11×25
after solutions
272z=272
z=272/272
z=1
x=3
y=1
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