Question

3x+4y+6z=16 4x+y-6z=24​

Answer 1

Step-by-step explanation:

On eliminating eq we get

$7x + 5y = 40 \\ = y = \frac{40 - 7x}{5}$

Putting eq we get

$3x + 4( \frac{40 - 7x}{5} ) + 6z = 16 \\ = \frac{15x + 160 - 28x + 30z}{5} = 16 \\ = 30z - 13x = 80 - 160 \\ = 30z - 13x = - 80$

$4x + \frac{40 - 7x}{5} - 6( \frac{13x - 80}{30} ) = 24 \\ = x = 0$

Taking value of z

$z = \frac{ - 80 + 13x}{30}$

Putting value of x and z in eq

y= 8 ,x= 0 ,z= -8/3